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Grade 11Mechanics

Question no 24, 25,26 please provide solutions to these three problems fastly

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Profile image of Sil
6 Years agoGrade 11
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1 Answer

Profile image of Arun
ApprovedApproved Tutor Answer6 Years ago
Dear student
 
20 = ½ * 10 * t^2
 
t = 2 sec
 
hence distance in 2nd second (last second) = ½ * 10 (2 *2 - 1) = 15 m