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Question in image from physics kinematics. Solve it pls

Question in image from physics kinematics.
Solve it pls

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Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
 
Assuming height of the tower h meter and time t we get,
=>h = 1/2gt^2 -------------------(i) 
Distance travelled in (t-1) secs, 
=>s = 1/2g(t-1)^2 ---------------(ii) 
Subtract both the eqns. we get,
=>11h/36 = 1/2g(2t - 1) ------------(iii) 
 11/36 x 1/2gt^2 = 1/2g(2t-1) 
=>11t^2 = 72t - 36 
=>11t^2 - 72t + 36 = 0 
On sollving further,
=>t = [72+/-60]/22 
=>t = 6 sec OR 0.55 sec 
Therefore. 
h = 176.40 m 
 
 
Regards
Arun (askIITians forum expert)

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