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Grade: 11
        
 
question 27 of chapter 10 rotation and rolling...///////////////////////////////
7 months ago

Answers : (1)

we will so
101 Points
							
A wheel rotating at a speed of 600 rpm.
0 = 600 rpm = 10 revolutions per second.
T = 10 sec. (In 10 sec. it comes to rest)
 = 0
Therefore 0 = –t
  = –10/10 = –1 rev/s2
  = 0 + t = 10 – 1 × 5 = 5 rev/s.
Therefore angular deacceleration = 1 rev/s2 and angular velocity of after 5 sec is 5 rev/s.
7 months ago
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