Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

question 27 of chapter 10 rotation and rolling...///////////////////////////////
2 years ago

## Answers : (1)

we will so
101 Points

A wheel rotating at a speed of 600 rpm.
0 = 600 rpm = 10 revolutions per second.
T = 10 sec. (In 10 sec. it comes to rest)
 = 0
Therefore 0 = –t
  = –10/10 = –1 rev/s2
  = 0 + t = 10 – 1 × 5 = 5 rev/s.
Therefore angular deacceleration = 1 rev/s2 and angular velocity of after 5 sec is 5 rev/s.
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions