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Question 23 sir please explain the approach to solve the problem 23 in earths inertial frame ?

satyam gupta , 9 Years ago
Grade 12th pass
anser 1 Answers
Rituraj Tiwari

Last Activity: 5 Years ago

frictional force between 2 and 3kg isμ1​×20=4Nfrictional force between 3 and 7kg isμ2​×50=15N
when 10N is applied on 2kg block
10−4=2a1​=6
a1​=3m/s2
as limiting friction is greater for 3kg block, it does not move
a2​=0
a3​=0
when 10N is applied on 3kg block
as limiting friction isgreater for 3kg block, it does not move
a1​=0
a2​=0
a3​=0
when 10N is applied on 7kg block
10=7a3​
a3​=1.43m/s2
a2​=1.43m/s2
10−4=2a1​=6
a1​=3m/s2

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