Question 23 sir please explain the approach to solve the problem 23 in earths inertial frame ?
satyam gupta , 9 Years ago
Grade 12th pass
Mechanics> Question 23 sir please explain the approa...
1 AnswersRituraj Tiwari
frictional force between 2 and 3kg isμ1×20=4Nfrictional force between 3 and 7kg isμ2×50=15N
when 10N is applied on 2kg block
10−4=2a1=6
a1=3m/s2
as limiting friction is greater for 3kg block, it does not move
a2=0
a3=0
when 10N is applied on 3kg block
as limiting friction isgreater for 3kg block, it does not move
a1=0
a2=0
a3=0
when 10N is applied on 7kg block
10=7a3
a3=1.43m/s2
a2=1.43m/s2
10−4=2a1=6
a1=3m/s2
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