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Question 21 solution

agam goel , 11 Years ago
Grade 12
anser 1 Answers
Sumit Majumdar
Dear student,
The maximum range of the projectile would be given by:
R_{max}=\frac{u^{2}}{g}+h=\frac{20^{2}}{10}+10=40+10=50 m
This range is maximum if the angle of projection is equal to 45 degree with horizontal.
Regards
Sumit
Last Activity: 11 Years ago
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