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Question 21 solution

Question 21 solution

Question Image
Grade:12

1 Answers

Sumit Majumdar IIT Delhi
askIITians Faculty 137 Points
7 years ago
Dear student,
The maximum range of the projectile would be given by:
R_{max}=\frac{u^{2}}{g}+h=\frac{20^{2}}{10}+10=40+10=50 m
This range is maximum if the angle of projection is equal to 45 degree with horizontal.
Regards
Sumit

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