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Grade 12Mechanics

Question 21 solution

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Profile image of agam  goel
12 Years agoGrade 12
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1 Answer

Profile image of Sumit Majumdar
11 Years ago
Dear student,
The maximum range of the projectile would be given by:
R_{max}=\frac{u^{2}}{g}+h=\frac{20^{2}}{10}+10=40+10=50 m
This range is maximum if the angle of projection is equal to 45 degree with horizontal.
Regards
Sumit