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`        question 19 of chapter 10 rotation and rolling...///////////////////////////////`
2 years ago

we will so
101 Points
```							A force of 6 N acting at an angle of 30° is just able to loosen the wrench at a distance 8 cm from it.Therefore total torque acting at A about the point 0= 6 sin 30° × (8/100)Therefore total torque required at B about the point 0= F × 16/100  F × 16/100 = 6 sin 30° × 8/100 F = (8 × 3) / 16 = 1.5 N.
```
2 years ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions