Flag Mechanics> Question 14 with explanation and without ...
question mark

Question 14 with explanation and without graphical method

Yash Raniwal , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun
Dear Yash
 
3 stages of motion: acceleration, constant velocity, deceleration
 
deceleration:
 
vf=vi+at
0 m/s = 24 m/s + (-4 m/s2)t
t=6 s
 
Δx =vi*t + 1/2* a* t2
Δx=(24m/s)(6s)+1/2 *(-4 m/s2)(6s)2
Δx=72 m
 
acceleration and constant velocity
 
time for acceleration t1 and constant velocity t2
t1+t2=50
distance for acceleration d1 and constant velocity d2
d1+d2=960
 
d1 = (vi+vf)/2)*t1
d1 = (0+24)/2)*t1
d1 = 12 m/s * t1
 
d2 = 24 m/s * t2
 
960 = 12 m/s * t1 + 24 m/s * t2
960 = 12 m/s *(50-t2) + 24 m/s * (t2)
960 = 12 m/s *t2 + 1200
360 = 12 m/s *t2
t2=30 s
t1=20 s
 
solve for a
vf = vi +at
24 m/s = 0 m/s + a (20 s)
a = 1.2 m/s2
 
Last Activity: 6 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments