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Grade 11Mechanics

Que. 3 and que. 5 pl refer to attached pic .urgent.

Question image for Que. 3 and que. 5 pl refer to attached pic .urgen

Arush Acharya

9 Years agoGrade 11

1 Answer

Shaswata Biswas

9 Years ago

Q.3 : Mass of bigger block = M. Mass of smaller blocks = m. Horizontal force = F.

Let the tension in the strings be T. And the acceleration of the bigger block be a.

Then, $a = \frac{F}{M}$

Coeffirof friction between the blocks is $\mu$

Then, friction on upper block, f₁ = $\mu mg$ .

Annd friction on lower block, f₂= $\mu F$ .

Now, for motion of upper block :

$ma = T - \mu mg$ ........... (1)

For motion of lower block :

$ma = mg - \mu F$ ......... (2)

(1) + (2)

$2ma = mg - \mu mg - \mu F$

=> $\frac{2mF}{M} + \mu F = mg(1 - \mu)$

=> $F = \frac{mg(1 - \mu)}{\frac{2m}{M} + \mu }$

From this expression, the maximum and minimum values of the force can be calculated.

THANKS

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