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Q.TWO BLOCK OF 5KG AND 7KG ARE CONNECTED BY A HEAVY ROPE OF MASS 4KG............A UPWARD FORCE OF 200N IS APPLIED ON THE UPPER BLOCK OF 5 KG A) WHAT IS ACCELERATION OF SYSTEM??????? B)WHAT IS TENSION AT TOP OF HEAVY ROD???????C)WHAT IS TENTION AT MIDPOINT OF ROD?????????

Q.TWO BLOCK OF 5KG AND 7KG ARE CONNECTED BY A HEAVY ROPE OF MASS 4KG............A UPWARD FORCE OF 200N IS APPLIED ON THE UPPER BLOCK OF 5 KG

A) WHAT IS ACCELERATION OF SYSTEM???????

B)WHAT IS TENSION  AT TOP OF HEAVY ROD???????C)WHAT IS TENTION AT MIDPOINT OF ROD?????????

Grade:12

2 Answers

Ashish Kumar
askIITians Faculty 32 Points
7 years ago
(a) F - (5+7+4)g=(5+7+4)a , F=200N, g= 10 m/s^2
a= 2.5 m/s^2
(b)The tension at top of the rod is pulling the rod as well as the block of 7 kg.
T=(4+7)a=11 *2.5= 27.5 N
(c) The tension at the midpoint is the pulling force for the lower half of rod as well as the 7kg block.
Tm=(2+7)a= 9*2.5= 22.5 N

169-2167_signature.GIF
Harsh gupta
13 Points
4 years ago
tension at the top of the heavy rope is of mass=7+4=11kgthe acceleration of system is 2.5 as we calculte in first part so here we can use puesdo force therefore T=ma +mg =m(a+g) =m×12.5 =11×12.5=137.5

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