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Q. THE RELATION BETWEEN TIME AND DISTANCE IS t=(A)x2 + (B)x, WHEREA AND B ARE CONSTANTS. THE RETARDATION IS - 2Av3 2Bv3 2ABv3 2B2v3

Bharat Makkar , 10 Years ago

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1 Answers

Sumit Majumdar

Last Activity: 10 Years ago

Dear student,
We have:
$t=Ax^{2}+Bx\Rightarrow \frac{d}{dt}t=A\left ( 2x \right )\frac{dx}{dt}+B\frac{dx}{dt}\Rightarrow 1=\left ( 2Ax+B \right )\frac{dx}{dt}\Rightarrow \frac{dx}{dt}=v=\frac{1}{2Ax+B}$
Therefore,
$\frac{dv}{dt}=\frac{-2A}{\left ( 2Ax+B \right )^{2}}=-2Av^{2}$
Regards
Sumit

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