Grade 12th passMechanics
Q.NO41-A particle is projected at an angle of 45° with the horizontal at a speed of 10m/s
1 Answer
KMS PRAVEEN
Horizontal component of velocity initially=30cos30°=25.95 m/s
Vertical component of velocity initially =30sin30°=15 m/s
Horizontal velocity after 1.5 sec=25.95 m/s
Vertical velocity after 1.5 sec=15-(9.81×1.5)=0.285 m/s
Therefore angle with horizontal=tan inverse (0.285/25.95)=0.6292°
SAME AS THIS U CAN SOLVE UR QUESYION TOO !
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