Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Q)An ant is at a corner of a cubical room of side a. The ant can move with a constant speed u.The minimum time taken to reach the farthest corner of the cube is: a)3a/u b)3 1/2 a/u c)5 1/2 a/u d)(2 1/2 +1)a/u PLZ solve it sir..

Q)An ant is at a corner of a cubical room of side a. The ant can move with a constant speed u.The minimum time taken to reach the farthest corner of the cube is:
a)3a/u   b)31/2a/u  c)51/2a/u  d)(21/2+1)a/u
PLZ solve it sir..
 

Grade:11

2 Answers

Saurabh Kumar
askIITians Faculty 2411 Points
6 years ago
Total distance covered = (21/2 + 1)a
speed = u
hence, time min = (21/2 + 1)a/u
Sanskar gupta
19 Points
4 years ago
You would might think the answer to be 3a or (sqrt2 + 1)a.....but the thing is that it`s neither of them.....now first of all open the cube and draw any two of its adjacent sides ....... therefore you will get a rectangle with the sides 2a and a....then for the last step draw the diagonal of the rectangle.......and find it .....the answer would be (sqrt5)a......and thus for the time divide it by `u` (given) so the answer is C) (sqrt5)a / u

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free