shashi K Sharma
Last Activity: 10 Years ago
Dear Bharat
The question asks of distance and you must be careful about it as the body changes its direction after maximum height(time=v/g)
Thus the body moves up till time = u/g & then down for rest time (4v/3g – v/g = v/3g =t’ say)
Thus the distance is maximum height plus the distance moved down.
the maximum height being (v2)/2g & the distance fallen in the aforesaid time t’ is ½gt’2
which comes as v2/18g. Thus the sum total of the two is 5v2/9g
