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`        Q.A particle starts form rest on a straight line. First it accelerates at 4 m/s2 for 10 seconds. Then for 10 seconds it moves with the acquired constant velocity. Then it decelerates at 8 m/s2 to rest. Total distance covered during the entire journey isChoose one:															500 m																600 m																700 m																800 m			 `
2 years ago

Arun
23742 Points
```							Dear studentFor 1st phase fromV1 = u + a* tV1 = 40 m/secV²1 = u² + 2 *a*sS = 1600/8 = 200 m Now for second phaseV2 = v1Now S = V2 *t = 40 * 10 = 400 m Gor third phase Initial velocity = V2 = 40 mFrom V²3 = V²2 - 2*a*sS = 1600/16 = 100 m Hence total distance covered = 200 + 400 + 100 = 700 m RegardsArun (askIITians forum expert)
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions