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Q. A BODY IS MOVING IN A CIRCLE AT A UNIFORM VELOCITY v. THE MAGNITUDE OF CHANGE IN VELOCITY WHEN THE RADIUS VECTOR DESCRIBES AN ANGLE OF 60⁰ IS-

4v

v/2

v

(3)^1/2v/2

Bharat Makkar

11 Years agoGrade Select Grade

3 Answers

Manabendra Nath Gaine

11 Years ago

Bharat Makkar

11 Years ago

but how? please give reason

shashi K Sharma

Approved Tutor Answer11 Years ago

The velocity vector is perpendicular to radius vector,LET v1 and v2 be the velocity vector(s) at the instant 1 and 2 respectively between which the angle described is 60degree

thus the angle between v2 vector and v1 vector is 60degree, the magnitude of each being v(as you said it is uniform circular motion)

thus the change is |v2 vector – v1 vector| =( v^2 +v^2 -2.v.v.Cos60)^.5 which is v

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​Q. A BODY IS MOVING IN A CIRCLE AT A UNIFORM VELOCITY v. THE MAGNITUDE OF CHANGE IN VELOCITY WHEN THE RADIUS VECTOR DESCRIBES AN ANGLE OF 600 IS- 4v v/2 v (3)1/2v/2

Bharat Makkar

3 Answers

Manabendra Nath Gaine

Bharat Makkar

shashi K Sharma

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Q. A BODY IS MOVING IN A CIRCLE AT A UNIFORM VELOCITY v. THE MAGNITUDE OF CHANGE IN VELOCITY WHEN THE RADIUS VECTOR DESCRIBES AN ANGLE OF 60⁰ IS-

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