Grade 11Mechanics

Q.A block starts moving on a horizontal plane under the influence of horizontal acceleration 'a'.After 'to' sec,the acceleration remains same in magnitude but reverses in direction.At what time does it come back to initial point?

Ans.(2+_/2)to

jiten

8 Years agoGrade 11

1 Answer

Karan Gupta

8 Years ago

At time ‘to’, v = u + at = 0 + a’to’ means v = ato.

Since, acceleration is in opposite direction now, the particle will come to a complete halt in another to, while covering a distance of a total of 2*(1/2*a*to^2) = a(to)^2

After covering distance of a(To)^2, particle starts its journey in reverse direction with zero initial velocity.

v^2 = 0 + 2*a*s [s= a(to)^2]

v^2 = 2*a*(a(to)^2)

v = sqrt(2)*a*to = a*t means t = sqrt (2)*to

Hence total time = to + to + sqrt(2)*to

=to(2+sqrt(2))

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Q.A block starts moving on a horizontal plane under the influence of horizontal acceleration 'a'.After 'to' sec,the acceleration remains same in magnitude but reverses in direction.At what time does it come back to initial point? Ans.(2+_/2)to

jiten

1 Answer

Karan Gupta

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