Q 15
Q 15
param , 10 Years ago
Grade
Mechanics> Q 15...
1 Answers
SHIVANSHU
v2=108-9x2
diff. both sides w.r.t to x
2v dv/dx = -18x
put v dv/dx=a(acceleration)
therefore a= -9x
use SHM condition :
a=- (omega)2 x
hence omega=3
for max amp. put v=0 toget x=root(12)
acc. to me the ans. r (B)and(C)
plz tell back if the solution is correct or not
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