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plzzzzzzzzzzzzzzz solve.........................................................................................

plzzzzzzzzzzzzzzz solve.........................................................................................

Question Image
Grade:12th pass

1 Answers

Khimraj
3007 Points
2 years ago
mass of left part of meter rule = (2/5)*3 = 6/5 kg at 20 cm from mark
similiarly mass of right part of meter rule = (3/5)*3 = 9/5 kg at 30 cm from 100cm mark
then to remain rule horizontal
(6/5)*10*20 + 7*30 = (9/5)*10*30 + w*60
24 +21 = 54 + 6w
w = -3/2 N
 

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