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Aryan , 5 Years ago

Grade 12th pass

1 Answers

Arun

Last Activity: 5 Years ago

Dear Aryan

Relative Velocity -

Relative velocity of a body, A with respected body B when the to bodies moving at an angle $\Theta$ .

$V_{AB}= \sqrt{V_{A}^{2}+V_{B}^{2}+2V_{A}V_{B}\cos \left ( 180-\theta \right )}$

$= \sqrt{V_{A}^{2}+V_{B}^{2}-2V_{A}V_{B}\cos \left ( \theta \right )}$

- wherein

$\\*V_{A}= velocity\: of\: A\\* V_{B}= velocity\: of\: B\\* \Theta = angle \: between \: A \: and \: B$

$\left | \Delta \vec{V} \right |=$ $\sqrt{\vec{V}_{1}^{2}+\vec{V}_{2}^{2}+2\vec{V}_{1}\vec{V}_{2}\cos \left ( \pi -\theta \right )}$

Since $\left | \vec{V_{1}} \right |=\left | \vec{V_{2}} \right |=\left | V \right |$

$\left |\Delta \vec{V} \right |=2 V \: \sin \frac{\Theta }{2}$

$=20\: \sin \: 30$

$= 10 m/s$

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