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Plz solve this 
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Grade:12th pass

1 Answers

Arun
25750 Points
4 years ago
Dear Aryan
 

Relative Velocity -

Relative velocity of a body, A with respected body B when the to bodies moving at an angle \Theta.

 

V_{AB}= \sqrt{V_{A}^{2}+V_{B}^{2}+2V_{A}V_{B}\cos \left ( 180-\theta \right )}

        = \sqrt{V_{A}^{2}+V_{B}^{2}-2V_{A}V_{B}\cos \left ( \theta \right )}

 

- wherein

\\*V_{A}= velocity\: of\: A\\* V_{B}= velocity\: of\: B\\* \Theta = angle \: between \: A \: and \: B

\left | \Delta \vec{V} \right |=\sqrt{\vec{V}_{1}^{2}+\vec{V}_{2}^{2}+2\vec{V}_{1}\vec{V}_{2}\cos \left ( \pi -\theta \right )}

Since \left | \vec{V_{1}} \right |=\left | \vec{V_{2}} \right |=\left | V \right |

\left |\Delta \vec{V} \right |=2 V \: \sin \frac{\Theta }{2}

=20\: \sin \: 30

= 10 m/s


 

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