PLZ HELPTwo bodies of masses m and 2m collide together with e=0.5 and relative approach speed of “u”. WHAT ISthe loss in K.E.?
Chinu , 7 Years ago
Grade 12th pass
1 Answers
Yuvrajpratapsingh
Last Activity: 7 Years ago
Let us first calculate centre of mass as relative speed is u, let us assume 2m mass is at rest:So we have mu+2m(0)= mV+2mv........1And e=(v-V)/u-0......2By solving above we have: u=2V and V=2v.......3Now loss in K.E is {m(2m)(1-e^2)(u rel ^2)} / 2(m+2m)After solving we have (mu^2)/4Hope that helps
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