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Plz help me solve the question .I tried it but ended up getting the wrong ans,so please help

Plz help me solve the question .I tried it but ended up getting the wrong ans,so please help

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Grade:11

2 Answers

Parth
58 Points
3 years ago
For A , t= 12s B t= 4s . on reaching ground velocity of B = 4*g*sin(theta) and velocity of A  = 12*g*sin(theta) {*theta = angle of incline}
But a will reach the ground after 8 seconds of B. so there will be some distance between A and B.
this distance  = 32*g*sin(theta). As A is faster it ‘ll catch up with B.
their x co-ordinate must same for catchup so For A 12*g*sin(theta)*t = 32*g*sin(theta) + x
and for B x = 4*g*sin(theta)*t . this gives t = 4s. so total time after release =  4+ 12 = 16 s
hence optiond
Vikas TU
14149 Points
3 years ago
Dear student
Hope you will get the solution . 
Please try to upload clear image, so that it is visible to all.
Good Luck 

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