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Grade: 11

                        

Plz help me solve the question .I tried it but ended up getting the wrong ans,so please help

5 months ago

Answers : (2)

Parth
58 Points
							
For A , t= 12s B t= 4s . on reaching ground velocity of B = 4*g*sin(theta) and velocity of A  = 12*g*sin(theta) {*theta = angle of incline}
But a will reach the ground after 8 seconds of B. so there will be some distance between A and B.
this distance  = 32*g*sin(theta). As A is faster it ‘ll catch up with B.
their x co-ordinate must same for catchup so For A 12*g*sin(theta)*t = 32*g*sin(theta) + x
and for B x = 4*g*sin(theta)*t . this gives t = 4s. so total time after release =  4+ 12 = 16 s
hence optiond
5 months ago
Vikas TU
12278 Points
							
Dear student
Hope you will get the solution . 
Please try to upload clear image, so that it is visible to all.
Good Luck 
5 months ago
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