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Grade: 11
```
Plz help me solve the question .I tried it but ended up getting the wrong ans,so please help

```
8 months ago

## Answers : (2)

Parth
58 Points
```							For A , t= 12s B t= 4s . on reaching ground velocity of B = 4*g*sin(theta) and velocity of A  = 12*g*sin(theta) {*theta = angle of incline}But a will reach the ground after 8 seconds of B. so there will be some distance between A and B.this distance  = 32*g*sin(theta). As A is faster it ‘ll catch up with B.their x co-ordinate must same for catchup so For A 12*g*sin(theta)*t = 32*g*sin(theta) + xand for B x = 4*g*sin(theta)*t . this gives t = 4s. so total time after release =  4+ 12 = 16 shence optiond
```
8 months ago
Vikas TU
14146 Points
```							Dear studentHope you will get the solution . Please try to upload clear image, so that it is visible to all.Good Luck
```
8 months ago
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