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Grade: 11

                        

Plz help me solve 4,5 plz tell me ho w to approach these problems

3 years ago

Answers : (1)

Chandan
121 Points
							
TRICKS AT THE END:
for 4:
to move block A towards right force F+umg should be slightly greater than spring force for convineance we will take it equal......................(1)
if the system is released from rest block B will move down
let us assume it moves down by x meters.
so will the spring be extended by x meters.
from statement 1:
kx=F+umg …............(2)    (k is the spring constant assumed,will cancel afterwards)
and as block goes doun by x meters,it will loose Mgx joules of energy which will be stored in the spring.
so kx2\2=Mgx
     kx=2Mg
putting the value of kx in eq 2
2Mg=F+umg
M=F\2g+um\2
TRICK:
NOTE:
not applicable for all but for many.
identify the forces on each component and write them down now make all the components in one line like make the block B horizontal at the level of others 
now as the forces are written on them,simple tension and f=ma will solve the problem.
 
 
for:5
the distance travelled =360\60 *r
=4pi\9
take the kinetic energy at that point 
and equate it to mv2\2 find v
centripetal accelaration=v2\r
using v2=u2+2as 
find a
and total accelaration = centripetal acceleration+a;
and hence find the angle using vestor method
UNFORTUNATELLY NO TRICk FOR SUCH TYPE OF QUESTIONS
hope it helped  
if yes please approve.
tankyou.
3 years ago
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