Grade 12th passMechanics

Plz help me out sir in these following two questions , with well explained steps and answers? I will be helpfull

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sohan goswami

8 Years agoGrade 12th pass

1 Answer

Pratham Sahu

8 Years ago

Q1.

mass of car=1400 kg

net force applied to the car=1500N

therefore acceleration=1500/1400=1.071m/s²

distance teavelled=100m.

Now we apply the formula

v²=u²+2aS as we have all the required quantities except v which we need to find

v²=0²+2*1.071*100

v=14.6 m/s

Q2.

Let the mass of the satellite is m

let speed of projection is v

The potential energy of the satellite at the earth= -GM_em/R_e²

The initial kinetic energy on earth=1/2*mv²

final potential energy in orbit=-GM_em/R_o²

Final kinetic energy=GM_em/2R_o

Now since the energy is conserved,

initial energy=final energy

-GM_em/R_e²+1/2*mv²=-GM_em/R_o²+GM_em/2R_o

Now substituting values

G=6.67*10^-11

M_e=6*10²⁴kg

R_o= 8000*10³m

R_e= 6400*10³m

we get the value of v to be as

v=7072m/s wkich is approx. 7.08 km/s

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Plz help me out sir in these following two questions , with well explained steps and answers? I will be helpfull

sohan goswami

1 Answer

Pratham Sahu

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