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`        Plz give the solution as soon as possible.urgently needed.`
one year ago

Arun
23044 Points
```							Dear student,We know that the forces acting on the hanging part of the chain are the weight of the hanging part, the tension (T) due to the part of chain in the tube and the normal reaction from ground(N). Let the length of chain remaining in tube be x and mass per unit of chain be λ.Therefore when we apply Newton’s second law on the hanging part of the chain, we getλhg−T−N=λhaNewton's second law for part in the tube,T=λxaNow if you substitute N = 0, you would be able to get the value of acceleration which would further give the velocity with which the end A will slip out. RegardsArun (askIITians forum expert)
```
one year ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions