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`        Plxxxx answer this question..?...its urgent.......soooonnnn....`
2 months ago

## Answers : (2)

```							a= sin(pit)+cos(pit)but a=dv/dtso dv/dt= sin(pit)+cos(pit)or dv= (sin(pit)+cos(pit))dtnow integrate both sidesv= (sin(pit) – cos(pit))/pi + Cbut at t=0, it is at rest or v=0 so that0 = C – 1/pi or C= 1/piso v= (sin(pit) – cos(pit))/pi + 1/pi= (sin(pit) – cos(pit) + 1)/pi now to find the max value of v, we simply need to find the max value of sin(pit) – cos(pit), which is root(1^2+(-1)^2)= root2so, v(max)= (root2 + 1)/pi m/soption 3 is correctkindly approve :)
```
2 months ago
```							Dear Student  a= sin(pit)+cos(pit)but a=dv/dtso dv/dt= sin(pit)+cos(pit)or dv= (sin(pit)+cos(pit))dtnow integrate both sidesv= (sin(pit) – cos(pit))/pi + Cbut at t=0, it is at rest or v=0 so that0 = C – 1/pi or C= 1/piso v= (sin(pit) – cos(pit))/pi + 1/pi= (sin(pit) – cos(pit) + 1)/pi now to find the max value of v, we simply need to find the max value of sin(pit) – cos(pit), which is root(1^2+(-1)^2)= root2so, v(max)= (root2 + 1)/pi m/s Regards
```
one month ago
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