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```
Pls somebody help me solve this ,you know it's really annoying me
Pls somebody help me solve this ,you know it's really annoying me

```
10 months ago

Mahek Raina
18 Points
```							We know, Hemispherical shell has centre of mass at a distance of R/2 from the plane surface.Taking N as normal force at point of contactFrictional coefficient uAnd angle of inclination of inclined plane equal to AAngle of friction as BAngle theta as CWe know: tanB= u Draw the free body diagram Balancing the forces on the shell we getN=mgcos(C-A)un=mgsin(C-A) From above equations we findtan(C-A) =uTherefore C-A=BA=C-B---------(I) For maximum theta or angle C we balance the momentabout Center of massN*(R*sin(C-B) /2) =uN*R(1-(cos(C-B))/2) sin(C-B) =tanB(2-cos(C-B)) Solving the above equation we get:C=sin-1(2(sinB))Theta=sin-1(2sin(lamda))
```
10 months ago
Vikas TU
14146 Points
```							Dear student Hope your doubt gets cleared Please refer the link below https://www.askiitians.com/iit-jee-physics/mechanics/centre-of-mass.aspxGood Luck
```
9 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions