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Grade: 12th pass
        
pls refer to the attachment
pls refer to the attachment
pls refer to the attachment
pls refer to the attachment
pls refer to the attachment
pls refer to the attachment
one year ago

Answers : (1)

Kenny Toijam
56 Points
							
Since the two blocks are moving together as they are in contact.Therefore the acceleration of the whole system is equal to the acceleration of the 2Kg mass
Now to calculate this question,Draw the F.B.D of the system of blocks.
The forces acting on the 6kg mass are:
1.(M+m)?gsin30
2.f1+f2 i.e Net friction acting on system
Now apply friction equations and find net force on system
fi=4gcos30*0.3                   f2=2gcos30*0.2
F(net)=(4+2)gsin30-(f1 +f2)
6a=6gsin30-8*(root over 3)
a=2.6m/s2.............which is the accn of the block 2kg too.

So the CORRECT OPTION IS (B)
HOPE IT HELPS......
Yours faithfully,
Kenny Toijam.
one year ago
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