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pls refer to the attachment pls refer to the attachment pls refer to the attachment pls refer to the attachment pls refer to the attachment pls refer to the attachment

pls refer to the attachment
pls refer to the attachment
pls refer to the attachment
pls refer to the attachment
pls refer to the attachment
pls refer to the attachment

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Grade:12th pass

1 Answers

Kenny Toijam
56 Points
7 years ago
Since the two blocks are moving together as they are in contact.Therefore the acceleration of the whole system is equal to the acceleration of the 2Kg mass
Now to calculate this question,Draw the F.B.D of the system of blocks.
The forces acting on the 6kg mass are:
1.(M+m)?gsin30
2.f1+f2 i.e Net friction acting on system
Now apply friction equations and find net force on system
fi=4gcos30*0.3                   f2=2gcos30*0.2
F(net)=(4+2)gsin30-(f1 +f2)
6a=6gsin30-8*(root over 3)
a=2.6m/s2.............which is the accn of the block 2kg too.

So the CORRECT OPTION IS (B)
HOPE IT HELPS......
Yours faithfully,
Kenny Toijam.

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