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Grade: 10

                        

Pls help me solve ques no. 18... ............................ ............. ..

4 years ago

Answers : (1)

Anshuman Mohanty
27 Points
							
Let the magnitude of the resultant be x
Now angle between OX and OB is (Φ – 90 )deg
In triangle XOB we have , cos (Φ -90) = x/6
=> sin Φ = x/6 ---- 1
And, (OX)^2 = x^2  = [ (OA)^2 + (OB)^2 +2(OA)(OB)cosΦ ]  (resultant formula) ----- 2

From 1 , x = 6sinΦ

Putiing values in 2 ,
36sin^2Φ = 16+36+48cosΦ

On solving we get Φ = 132 deg.

 
4 years ago
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