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```
Pls help me solve ques no. 18... ............................ ............. ..
Pls help me solve ques no. 18... ............................ ............. ..

```
4 years ago

Anshuman Mohanty
27 Points
```							Let the magnitude of the resultant be xNow angle between OX and OB is (Φ – 90 )degIn triangle XOB we have , cos (Φ -90) = x/6=> sin Φ = x/6 ---- 1And, (OX)^2 = x^2  = [ (OA)^2 + (OB)^2 +2(OA)(OB)cosΦ ]  (resultant formula) ----- 2From 1 , x = 6sinΦPutiing values in 2 ,36sin^2Φ = 16+36+48cosΦOn solving we get Φ = 132 deg.
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions