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Grade: 12th pass

                        

pls explain how to solve this qn.....................................................................................

5 months ago

Answers : (1)

Mahashay Jee
13 Points
							
For both blocks to remain together the force of friction between 5kg and 10kg is responsible for movement of 5kg block because that is only force to act on 5kg block in horizontal direction and assume both frictions to be at their maximum value i.e.  Muu times normal reaction and calculate value of frictions by caluculating both normal reactions and calculate 5kg block acceleration to put it in 10kg's force equation to find maximum value of F that is 105N
5 months ago
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