Grade 11Mechanics
Please solve this questionAnswer is Option A : mg Why is it mg?
Please solve this question
Answer is Option A : mg
Why is it mg?
1 Answer
Arun
Approved Tutor Answer6 Years agoIf the reaction is N then
Frictional force=u N (u is coefficient of friction).
Since block is placed on the inclined plane, so
N=mg Cos (theta)
m is the mass of the body placed on the plane.
Here N and uN both the forces are applied on the block by the inclined plane and both are acting at right angle between them, therefore total force applied on the block by the inclined plane is
F (net)=[(uN)^2+N^2]^(1/2)
Frictional force=u N (u is coefficient of friction).
Since block is placed on the inclined plane, so
N=mg Cos (theta)
m is the mass of the body placed on the plane.
Here N and uN both the forces are applied on the block by the inclined plane and both are acting at right angle between them, therefore total force applied on the block by the inclined plane is
F (net)=[(uN)^2+N^2]^(1/2)
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