Please solve this answer of the given attachment by showing all the steps.
Debayan das , 7 Years ago
Grade 11
1 Answers
vishal
Last Activity: 7 Years ago
This question can easily be done by using mechanical energy conservation law (KE)1 + (PE)1 = Ke2 + pe20 + mgh = m.5×v^2 + mg×.5h0+ m×10×1 =m×.5× v^2 + 5mm is cancelled out10 = 5 + v^2×.5v=√10by projectile motionTime of flight is = 1/√10Then distance covered is equal to Velocity × time √10 × 1/√10= 1 meter
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free