Grade 11Mechanics
Please solve this answer of the given attachment by showing all the steps.
1 Answer
vishal
This question can easily be done by using mechanical energy conservation law (KE)1 + (PE)1 = Ke2 + pe20 + mgh = m.5×v^2 + mg×.5h0+ m×10×1 =m×.5× v^2 + 5mm is cancelled out10 = 5 + v^2×.5v=√10by projectile motionTime of flight is = 1/√10Then distance covered is equal to Velocity × time √10 × 1/√10= 1 meter
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