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`        Please solve the question in the attachment...................... `
8 months ago

SARTHAK TOMAR
14 Points
```							The answer will be d bcoz first the acceleration is negative hence velocity decrease but does not become zero and after that the vice versa. Hope u get the answr
```
8 months ago
SARTHAK TOMAR
14 Points
```							The answer will be A because first the displacement is decreasing and therefore velocity should be negative and should increase upto t=1 but suddenly after t=1 the displacement starts to increase. Therefore we can say graph mentioned in (a) will be correct
```
8 months ago
Pratik Kumawat
40 Points
```							Hey Pawan joshi,lets move towards the solutionIn the first curve displacement(s) is decreasing with increase in time .and you can see the curve is like a parabola in only first quadrant having eqn t2= -4as (refer notes of parabola).differentiating it , we will get  ds/dt = -(1/4a)*2t , where ds/dt is velocity.and it is negative and linearly dependent on time .for curve between t=1 and t=2 ,the slope of curve is decreasing linearly and it is always positive .so Option A is correct.    Pratik KumawatIIT(ISM) Dhanbad
```
8 months ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions