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Please solve the question attached. It’s from Motion in a straight line.

Raghav , 6 Years ago
Grade 12
anser 1 Answers
Arun
h=ut1−12gt21−h=ut1−12gt12--------(i)h=ut2+12h=ut2+12gt22gt22--------(ii)Where h is a positive number. Multiplying (i) by t2t2 and (ii) by t1t1 we get,h(t1+t2)=12=12h(t1+t2)=12=12gt1t2(t1+t2)gt1t2(t1+t2)-----------(iii)y=12y=12gt2gt2---------(iv)From (iii) and (iv)t=t1t2−−−√t=t1t2
Last Activity: 6 Years ago
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