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`        Please sir solve this Q.Q-A ball falls from a height h over a inclined plane of a 30(see attachment).After collision ,ball moves horizontally, the coefficient of restitution is Ans-1/3`
one year ago

Khimraj
3008 Points
```							Coefficient of restitution is defined as the ratio of velocity of separation and velocity of approach along the line of impact.Let the velocity of ball before colliding horizontal surface is u, then velocity is u cos θGiven that particle moves after collision in horizontal direction, so the velocity of the particle just after the collision along the direction of line of impact is v sin θ   The coefficient of restitution is,e=vsinθ/u cos θ= (v/u)tan θhere v = utanθso e = tan2θ = 1/3Hope it clears...........................
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions