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`        Please explain this question. I tried it many times but failed.I don't understand the meaning of normal reaction on hinge meaning here.I asked it previously also but got wrong answer .Plss.....help me out in this.Q-A uniform rod of length L and mass M is held horizontally with the help of one light vertical string and a hinge as shown.If the string is cut suddenly,find out the initial normal reaction on the hingeCorrect answer is Mg/4(This anwer is correct.Please help me.)`
one year ago

Arun
23478 Points
```							 take the center of mass as axis of rotation,the net torque is zero in initial state.Ta=Tb =>Fa×ra=Fb×rbhere Ta is torque by hinge and Tb is torque by the rope.ra=rb because the axis of rotation is at the center of the rod.from this we get our both the forces to be equal.and the net forces are zerothe forces upward i.e.Fa and Fb are opposed by a force downwardsthe only force downwards is mgFa +Fb=mg2Fa=mg   …......from our calculation above.Fa=mg/2after cutting the rope the force on right is removed but force on ,left acts as normal reaction and this is equal to mg/2.
```
one year ago
Kaushki
19 Points
```							Thank you so much.Now ,I understand it properly.….............................................................
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions