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Grade: 11
Please asweR this question of mechanics I am facing difficulty
2 years ago

## Answers : (1)

SRC Jayanth
57 Points

Let the time after which the first one overtakes the second be ‘t’
then distance travelled by first train in ‘t’ sec= 30t
[distance = speed x time]
the distance travelled by second train in ‘t’ sec= 20t

30t= 20t + 200 [also it has to cross the train]
10t = 200
t=10 s

200m
>                               300m
>

After some time ‘t’
>
-                            >
2 years ago
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