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Please asweR this question of mechanics I am facing difficulty

Please asweR this question of mechanics I am facing difficulty

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Grade:11

1 Answers

SRC Jayanth
57 Points
7 years ago
Let the time after which the first one overtakes the second be ‘t’
then distance travelled by first train in ‘t’ sec= 30t
[distance = speed x time]
 the distance travelled by second train in ‘t’ sec= 20t
 
30t= 20t + 200 [also it has to cross the train]
10t = 200
t=10 s
 
    200m
                     >                               300m
                                                                              >
 
                                                                                            
After some time ‘t’
                                                                                            >
                                -                            >

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