Grade 12Mechanics
Please answer this question. Explain this solution in detail.
1 Answer
Vaidehi
If a body of mass m is thrown vertically upwards with th a velocity v,the maximum ht h can be found from the relation: 1/2mv^2=(GMm/R)-(GMm/R+h) h=v^2*R/(2gR-v^2)v=1/2 (escpe vlcty) and V.E=2gRSubstituting this in eqn of ht we get h as R/3
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