Please answer the attached question. Please................ ......
Parth Verma , 7 Years ago
Grade 12th Pass
Mechanics> Please answer the attached question. Plea...
1 Answers
Arun
Dear Parth
Let density of ball is ρ
Then density of water is 2ρ [ as question said density of ball is half of density of water ]
Let mass of ball is m , then volume of ball is m/ρ
Then density of water is 2ρ [ as question said density of ball is half of density of water ]
Let mass of ball is m , then volume of ball is m/ρ
Now, on striking water surface , potential energy of ball = mgh = mg × 10m [ as height is 10m ]
Due to buoyancy ,
Net force opposes the motion of ball = upthrust - weight of ball
= (Volume of ball × density of water × g) - mg
= m/ρ × 2ρ × g - mg = 2mg - mg
Due to buoyancy ,
Net force opposes the motion of ball = upthrust - weight of ball
= (Volume of ball × density of water × g) - mg
= m/ρ × 2ρ × g - mg = 2mg - mg
let ball goes h depth in water.
then potential energy of ball in h depth = mg × h
then potential energy of ball in h depth = mg × h
Use wrok energy theorem,
potential energy of ball on water surface = potential energy of ball in h depth of water
mg × 10m = mg × h
h = 10
potential energy of ball on water surface = potential energy of ball in h depth of water
mg × 10m = mg × h
h = 10
Hence, answer should be 10 m
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