Let m1 and m2 be masses of satellites P1 and P2.
If M is mass of the earth, then
GMm1/R^2=m1v1^2/R OR
GM/R=v1^2 OR
v1=(GM/R)^1/2……..(1)
Similarly,for P2 satellite,
v2=(GM/4R)^1/2………..(2)
Then, linear velocity of P2 relative to P1 is v2-v1.
When both satellites will be nearest to each other,
angular velocity of the line joining them will be maximum. This maximum angular velocity will be
w( max)=(v2-v1)/3R= (GM)^1/2[ (1/4R)^1/2-(1/R)^1/2]/3R and for maximum distance of 5R between them
w(min.)=(GM)^1/2 [ (1/4R)^1/2-(1/R)^1/2]/5R. Then,
w(max)/w(min)=1/3R/(1/5R)=5/3
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
Last Activity: 10 Months ago
A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
11
21
31
41
Last Activity: 10 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
