Grade 11Mechanics
Please anser this question.related to laws of motion
1 Answer
SRC Jayanth
Let the time after which the first one overtakes the second be ‘t’
then distance travelled by first train in ‘t’ sec= 30t
[distance = speed x time]
the distance travelled by second train in ‘t’ sec= 20t
30t= 20t + 200 [also it has to cross the train]
10t = 200
t=10 s
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