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Please anser this question.related to laws of motion

Krishna sagar , 7 Years ago
Grade 11
anser 1 Answers
SRC Jayanth

Last Activity: 7 Years ago

 
Let the time after which the first one overtakes the second be ‘t’
then distance travelled by first train in ‘t’ sec= 30t
[distance = speed x time]
 the distance travelled by second train in ‘t’ sec= 20t
 
30t= 20t + 200 [also it has to cross the train]
10t = 200
t=10 s

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