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`        Please anser this question.related to laws of motion`
2 years ago

SRC Jayanth
57 Points
```							 Let the time after which the first one overtakes the second be ‘t’then distance travelled by first train in ‘t’ sec= 30t[distance = speed x time] the distance travelled by second train in ‘t’ sec= 20t 30t= 20t + 200 [also it has to cross the train]10t = 200t=10 s
```
2 years ago
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