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Particle of mass 2m is connected by an inextensible string of length 1.2 m to a ring of mass M which is free to slide on a horizontal smooth rod initially the ring and the particle are at same level with the string taught what are generally simultaneously the distance in metre moved by the ring when the string become verticle is
Dear Aksh mx = (1.2 – x) * 2m mx = 2.4 m – 2mx mx = 0.8m x = 0.8 metres x is the distance from the initial point of ring
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