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Grade 11Mechanics

One cosmic-ray proton approaches the Earth along its axis with a velocity of 0.787c toward the north pole and another, with velocity 0.612c, toward the south pole. See Fig. 20-24. Find the relative speed of approach of one particle with respect to the other. (Hint: It is useful to consider the Earth and one of the particles as the two inertial reference frames.)
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

Profile image of Simran Bhatia
11 Years agoGrade 11
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1 Answer

Profile image of Aditi Chauhan
11 Years ago
To find out the relative speed of approach of one particle with respect to the other, substitute 0.787c for v0, 0.612c for u in the equation v = (v0 + u) / (1 + v0u/c2),
v = (v0 + u) / (1 + v0u/c2)
= (0.787c + 0.612c) / (1+(0.787c) (0.612c)/c2)
= 1.399c / (1+0.4816)
= 0.944c
From the above observation we conclude that, the relative speed of approach of one particle with respect to the other would be 0.944c.