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# Neglecting friction everywhere,find the acceleration of mass M,assume m>m'......with solution, please help me solving such questions which have blocks connected to pulleys which are moving relative to another moving block.

Grade:12th pass

## 1 Answers

Ayush_Deep
120 Points
one year ago
Consider the two blocks m and m' moving in horizontal motion.
Their acceleration are g/2 but in opposite direction.
Since their is not external force the acceleration of center of mass will be zero.
Since the heavier mass m>m' moves in -ve x axis by g/2 acceleration the whole system will move towards +be x axis with an acceleration a.
No net force
m1a1+m2a2+m3a3+m4a4+..... = 0
-mg/2 + m'g/2 + (2m+2m'+M)*a=0
a= (m-m')g/2(2m+2m'+M)
Hope you got correct answer.

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