motion of a particle along a straight line is described by function of X= (2t-3)2 where X is in metres and t is in seconds . Find:(a) position, velocity, acceleration at t=2s(b) velocity of a particle at origin
shalmali pathak , 7 Years ago
Grade 11
1 Answers
Aman gohel
Last Activity: 7 Years ago
X=4t^2-12t+9....(i)=>Differentiating X w.r.t t=>dX/dt=>d(4t^2-12t+9)/dt=>v=8t-12.....(ii)Differentiating v w.r.t t=>dV/dt=>d(8t-12)/dt=>a=8...(iii)Therefor,from equal...(I)=>X=1m(Ans)For equa....(ii)=>V=4m/s(Ans)As a is constant which is 8m/s^2(Ans)B. Given,(2t-3)^2=0 =>t=3/2sVelocity at time t=0 is:-=>V=0[From equa...(ii)(Ans)