badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

Moment of inertia of a uniform circular disc about its diameter is l. Its moment of inertia about an axis parallel to its plane and passing through a point on its rim will be what???

2 years ago

Answers : (2)

Aakash
21 Points
							About diameter =(MR^2)/4And about point passing through rim:Using parallel axis theorem:(MR^2)/4  +  MR^2=(5MR^2)/4
						
2 years ago
chandana chandhu
5 Points
							
By the principle of parallel axis,
I={MR^2/4}+MR^2=5MR^2/4,for a tangent parallel to diameter
For a tangent parallel to axis passing through its center and perpendicular to its plane 
I={MR^2/2}+MR^2=3MR^2/2
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details