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Moment of inertia of a uniform circular disc about its diameter is l. Its moment of inertia about an axis parallel to its plane and passing through a point on its rim will be what???
About diameter =(MR^2)/4And about point passing through rim:Using parallel axis theorem:(MR^2)/4 + MR^2=(5MR^2)/4
By the principle of parallel axis,I={MR^2/4}+MR^2=5MR^2/4,for a tangent parallel to diameterFor a tangent parallel to axis passing through its center and perpendicular to its plane I={MR^2/2}+MR^2=3MR^2/2
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