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maximum height reached by projectile is 4m. The horizontal range is 12m. velocity of projection?

maximum height reached by projectile is 4m. The horizontal range is 12m. velocity of projection?

Grade:12

1 Answers

Arun
25750 Points
6 years ago
Dear Student
 
H  = (R tan Ф ) / 4 
4  = (12 tan Ф ) / 4

tan Ф = 4/3        sin 2Ф = 2 tan Ф / (1 + tan² Ф)  = 0.96

R = u² sin 2Ф / g  

u² =  12 * g / 0.96  = 25 g /2 

u = 5 √(g/2)
 
Regards
Arun (askIITians forum expert)

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