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Grade: 12
        
mass M is divided into two parts xm and (1-xm). for a given separtion the value of x for which gravitationl attraction between two piceces of mass becomes maximum
 
one year ago

Answers : (2)

Vikas TU
6874 Points
							
Fnet = G(xm) (1-xm)/x^2
For maxima we need to differentiate it,
Hence,
Fnet = Gm(1-xm)/x
Gm[-m*x + 1.(1-xm)]/x^2 = 0
(1-xm) = mx
2mx = 1
x = 1/2m meter.
where m is the mass.
Put x in Fnet we get,
Fnet = G/4x^2 N.
one year ago
Ashutosh Mohan Sharma
askIITians Faculty
180 Points
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one year ago
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