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mass M is divided into two parts xm and (1-xm). for a given separtion the value of x for which gravitationl attraction between two piceces of mass becomes maximum
Fnet = G(xm) (1-xm)/x^2For maxima we need to differentiate it,Hence,Fnet = Gm(1-xm)/xGm[-m*x + 1.(1-xm)]/x^2 = 0(1-xm) = mx2mx = 1x = 1/2m meter.where m is the mass.Put x in Fnet we get,Fnet = G/4x^2 N.
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