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Liquid mercury (viscosity = 1.55 × 10 –3 N ∙ s/m 2 ) flows through a horizontal pipe of internal radius 1.88 cm and length 1.26 m. The volume flux is 5.35 × 10 –2 L/min. (a) Show that the flow is laminar. (b) Calculate the difference in pressure between the two ends of the pipe.

Liquid mercury (viscosity = 1.55 × 10–3 N ∙ s/m2) flows through a horizontal pipe of internal radius 1.88 cm and length 1.26 m. The volume flux is 5.35 × 10–2 L/min. (a) Show that the flow is laminar. (b) Calculate the difference in pressure between the two ends of the pipe.

Grade:upto college level

1 Answers

Deepak Patra
askIITians Faculty 471 Points
8 years ago
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