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Grade: upto college level
        
Liquid mercury (viscosity = 1.55 × 10–3 N ∙ s/m2) flows through a horizontal pipe of internal radius 1.88 cm and length 1.26 m. The volume flux is 5.35 × 10–2 L/min. (a) Show that the flow is laminar. (b) Calculate the difference in pressure between the two ends of the pipe.
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
471 Points
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3 years ago
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Course Features

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  • Discussion Forum
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