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Liquid mercury (viscosity = 1.55 × 10–3 N ∙ s/m2) flows through a horizontal pipe of internal radius 1.88 cm and length 1.26 m. The volume flux is 5.35 × 10–2 L/min. (a) Show that the flow is laminar. (b) Calculate the difference in pressure between the two ends of the pipe.

Shane Macguire , 9 Years ago
Grade upto college level
anser 1 Answers
Deepak Patra

Last Activity: 9 Years ago

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