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Grade 12Mechanics

kindly solve this question

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I have used the equations properly but i dont know whether it is correct

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pradeep

10 Years agoGrade 12

1 Answer

Riddhish Bhalodia

10 Years ago

For the wedge not to move
$F_h = \mu N$
$F_h$ is the horizontal component of the force applied by the air
and N = mg + F_v
Fv is the vertical component of the force of the air
Now F on the wedge perpendicular to the inclined surface is
dV = Adx (the differential volume)
hence
$dm = \rho dV = \rho Adx$
Now
$dF = dm v \frac{dv}{dx} = \rho A vdv$
hence we get
$F = \rho A v^2/2$
and hence
$F_h = \rho A v^2sin\theta/2, \quad F_v = \rho Av^2cos\theta/2$
Now solve it

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