It was calculated that a shell fired from a gun with a certain velocity and at an angle of elevation 5pi/36 rad should strike a given terget.In actual practice,it was found that a hill just prevented the trajectory.At what angle of elevation should the gun be fired to hit the target?-\t5pi/36\t11pi/36\t7pi/36\t13pi/36
papan roy , 7 Years ago
Grade 12th pass
1 Answers
Namit sharma
Last Activity: 7 Years ago
According to question,A hill just prevented the trajectory. In this case a shell should be fired at angle (π2−θ), so that it can hit the target.Thus, the required angle of elevation is given as,π2−5π36=18π−5π36=13π36 radian
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